Higher November 2020 Paper 1 Q2
2 Here is vector \(\mathbf{a}\).

Circle the column vector that represents \(\mathbf{a}\). [1 mark]
- \(\begin{pmatrix}3\\2\end{pmatrix}\)
- \(\begin{pmatrix}-3\\2\end{pmatrix}\)
- \(\begin{pmatrix}3\\-2\end{pmatrix}\)
- \(\begin{pmatrix}-3\\-2\end{pmatrix}\)
| Answer | Mark | Comments |
|---|---|---|
| \(\begin{pmatrix}3\\-2\end{pmatrix}\) | B1 |