Higher June 2018 Paper 2 Q18
18 The solution of \(\quad 3^x = 300 \quad\) lies between two consecutive integers.
Work out the two integers. [1 mark]
| Answer | Mark | Comments |
|---|---|---|
| 5 and 6 with no incorrect evaluation seen for \(3^5\) or \(3^6\) or 5 and 6 with no incorrect evaluation seen for \(\sqrt[5]{300}\) or \(\sqrt[6]{300}\) | B1 | 5 and 6 in either order allow any evaluations truncated or rounded to 2 sf or 1 sf |
Additional guidance
| 5 and 6 with either \(3^5\) or \(3^6\) evaluated incorrectly | B0 |
| \(3^5\) or \(3^6\) | B0 |
| 243 and 729 | B0 |
| \(3^5 = 243\) Allow 240 or 200 (with no incorrect value seen) \(3^6 = 729\) Allow 720 or 730 or 700 (with no incorrect value seen) | |
| \(\sqrt[5]{300} = 3.1(2\ldots)\) or 3.13 \(\sqrt[6]{300} = 2.5(8\ldots)\) or 2.59 or 2.6 |