Higher June 2018 Paper 1 Q2
2 The vector \(\begin{pmatrix} -2 \\ 3 \end{pmatrix}\) translates A to B.
Circle the vector that translates B to A. [1 mark]
- \(\begin{pmatrix} -2 \\ 3 \end{pmatrix}\)
- \(\begin{pmatrix} -3 \\ 2 \end{pmatrix}\)
- \(\begin{pmatrix} 3 \\ -2 \end{pmatrix}\)
- \(\begin{pmatrix} 2 \\ -3 \end{pmatrix}\)
| Answer | Mark | Comments |
|---|---|---|
| \(\begin{pmatrix} 2 \\ -3 \end{pmatrix}\) | B1 |