Foundation November 2019 Paper 1 Q27
27 Write \(\quad 27 \times \left(3^2\right)^7 \quad\) as a single power of 3 [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| \((27 =)\ 3^3\) | M1 | |
| \(\left(\left(3^2\right)^7 =\right)\ 3^{2 \times 7}\) or \(\left(\left(3^2\right)^7 =\right)\ 3^{14}\) | M1 | |
| \(3^{17}\) | A1ft | ft \(3^a\) and \(3^b\) then answer \(3^{a + b}\) with M1M0 or M0M1 scored |
Additional guidance
| Answer \(3^{17}\) with no incorrect working | M1M1A1 |
| \(3^{17}\) in working with 17 on the answer line or both \(3^{17}\) and 17 on the answer line | M1M1A1 |
| \(3^3 \times 3^9 = 3^{12}\) | M1M0A1ft |
| Evaluation of powers of 3 as values only | M0M0A0 |
| Answer 17 with no valid working | M0M0A0 |