Foundation June 2019 Paper 1 Q23
23 Work out the value of \(\quad (3^{12} \div 3^5) \div (3^2 \times 3)\) [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| \((3^{12} =)\ 531\,441\) or \((3^5 =)\ 243\) or \((3^{12} \div 3^5 =)\ 3^7\) or \((3^{12} \div 3^5 =)\ 2187\) or \((3^2 \times 3 =)\ 3^3\) or \((3^2 \times 3 =)\ 27\) or \(3^{12} \div 3^5 \div 3^2 \div 3\) or \(\dfrac{3^{12}}{3^5} \times \dfrac{1}{3^2 \times 3}\) | M1 | |
| \(3^7 \div 3^3\) or \(3^7 \div 27\) or \(3^{(12 - 5 - 2 - 1)}\) or \(\dfrac{3^{12}}{3^8}\) or \(3^4\) or \(2187 \div 27\) | M1dep | oe in the form \(3^n \div 3^{(n - 4)}\) |
| 81 | A1 |
Additional guidance
| \(3^4\) and 81 on the answer line in either order | M1M1A1 |
| 81 in working and \(3^4\) on the answer line | M1M1A0 |