Foundation June 2025 Paper 1 Q26
26 \(\mathbf{c} = \begin{pmatrix} 7 \\ 4 \end{pmatrix} \qquad \mathbf{d} = \begin{pmatrix} 2 \\ -1 \end{pmatrix}\)
Work out \(2\mathbf{c} + 3\mathbf{d}\)
Give your answer as a column vector. (2)
| Answer | Mark | Mark scheme |
|---|---|---|
| \(\begin{pmatrix} 20 \\ 5 \end{pmatrix}\) | M1 | for \(2\begin{pmatrix} 7 \\ 4 \end{pmatrix} + 3\begin{pmatrix} 2 \\ -1 \end{pmatrix}\) or \(\begin{pmatrix} 14 \\ 8 \end{pmatrix}\) and \(\begin{pmatrix} 6 \\ -3 \end{pmatrix}\) or \(\begin{pmatrix} 20 \\ y \end{pmatrix}\) or \(\begin{pmatrix} x \\ 5 \end{pmatrix}\) |
| A1 | for \(\begin{pmatrix} 20 \\ 5 \end{pmatrix}\) or \(5\begin{pmatrix} 4 \\ 1 \end{pmatrix}\) |
Additional guidance
For M1 condone without bracket and/or with fraction line.
Correct answer spoilt scores M1A0