Foundation November 2023 Paper 2 Q20
20 Use Pythagoras’ theorem to work out the value of \(x\). [3 marks]
Not drawn accurately
| Answer | Mark | Comments |
|---|---|---|
| \(12.9^2\) or 166.41 and \(17.2^2\) or 295.84 | M1 | implied by 462.25 or 129.43 or \(\sqrt{129.43}\) or 11.37… or 11.38 or 11.4 |
| \(\sqrt{12.9^2 + 17.2^2}\) or \(\sqrt{166.41 + 295.84}\) or \(\sqrt{462.25}\) | M1dep | |
| 21.5 | A1 | oe |
Additional guidance
| Correct answer with no working | M1M1A1 |
| 21.5 with error seen is A0 eg \(\sqrt{12.9^2 + 17.2^2} = \sqrt{461.95}\) Answer 21.5 | M1M1A0 |
| Answer from trigonometry or drawing | M0M0A0 |