Higher November 2024 Paper 2 Q11
11
Diagram NOT accurately drawn
\(ABCDE\) is a regular pentagon.
\(DEFGHI\) is a regular hexagon.
\(AF\) is a straight line.
Work out the size of angle \(EAF\)
(5)
| Scheme | Marks |
|---|---|
| int angle of pentagon = (3 × 180) ÷ 5 (= 108) oe or ext angle of pentagon = 360 ÷ 5 (= 72) oe | M1 |
| int angle of hexagon = (4 × 180) ÷ 6 (= 120) or ext angle of hexagon = 360 ÷ 6 (= 60) | M1 |
| 360 – (“108” + “120”) (= 132) oe or “60” + “72” (= 132) or (180 – “108”) + (180 – “120”) (= 132) | M1 |
[180 – (“60” + “72”)] ÷ 2 oe or \(\dfrac{180 - \text{``}{132}\text{''}}{2}\) oe or [180 – (180 – “108”) – (180 – “120”)] ÷ 2 oe | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: 24 | A1 |
| (5) | |
| (5 marks) |
Notes
M1: allow in working but not if labelled in wrong place on diagram (unless clearly started again)
M1: allow in working but not if labelled in wrong place on diagram (unless clearly started again)
M1: A fully correct method to find the size of obtuse angle \(AEF\) but not if labelled in wrong place on diagram
[Figures in inverted commas must come from correct working]
M1: A fully correct method to find the size of angle \(EAF\)
[Figures in inverted commas must come from correct working]
A1: cao