Higher November 2024 Paper 3 Q15
15 Make \(p\) the subject of the formula \(\qquad t = \dfrac{2(2p - 3)}{5 - 2p}\) (4)
| Answer | Mark | Mark scheme |
|---|---|---|
| \(p = \dfrac{5t + 6}{4 + 2t}\) | M1 | for clearing the fraction eg \(t(5 - 2p) = 2(2p - 3)\) or \(5t - 2pt = 4p - 6\) |
| M1 | (dep M1) for isolating \(p\) terms in a correct equation eg \(4p + 2pt = 5t + 6\) | |
| M1 | (dep on two terms in \(p\) of the form \(ap + bpt\)) for factorising eg \(p(4 + 2t) = 5t + 6\) | |
| A1 | for \(p = \dfrac{5t + 6}{4 + 2t}\) or \(p = \dfrac{5t + 6}{2(2 + t)}\) oe eg \(p = \dfrac{-6 - 5t}{-4 - 2t}\) |
Additional guidance
Condone error in expansion of RHS for this mark
\(a\) and \(b\) are non zero integers