A2 October 2020 Q1
1. A small sports club has 12 adult members and 14 junior members.
The club needs to enter a team of 8 players for a particular competition.
Determine the number of ways in which the team can be selected if
| Scheme | Marks | AO |
|---|---|---|
| \({}^{26}C_{8} = 1562275\) | B1 | 1.1b |
| (1) |
Notes
B1: Correct answer 1562275 (no need to see calculation)
| Scheme | Marks | AO |
|---|---|---|
| Attempts \({}^{12}C_{4} \times {}^{14}C_{4}\) | M1 | 1.1b |
| \(= 495 \times 1001 = 495495\) | A1 | 1.1b |
| (2) |
Notes
M1: Attempts the product shown.
A1: 495495
| Scheme | Marks | AO |
|---|---|---|
| Attempts cases for 5, 6, 7 or 8 adults on team (only). | M1 | 3.1a |
| \({}^{12}C_{5} \times {}^{14}C_{3} + {}^{12}C_{6} \times {}^{14}C_{2} + {}^{12}C_{7} \times {}^{14}C_{1} + {}^{12}C_{8} \times {}^{14}C_{0} = \ldots\) | M1 | 1.1b |
| = 383955 | A1 | 1.1b |
| (3) | ||
| (6 marks) |
Notes
M1: Works out the different cases that give more than half adults – e.g. attempts to find combinations for 5, 6, 7 or 8 adults (or 0, 1, 2 or 3 juniors). Need not be the correct formula, look for evidence of the correct cases considered. Do not allow this mark if the case of 4 adults and 4 juniors is included.
M1: Sums the possibilities. Allow if the 4 adults/4 juniors case is included, but the binomial products must be correct but e.g. \({}^{14}C_{0}\) may not be seen (as it is 1). Must be an attempt at using the correct formulae.
A1: cao 383955