June 2022 Paper 1 Q2
2 Express \(\dfrac{13-x}{(x-3)(x+2)}\) in partial fractions. [3]
| Scheme | Marks | AO |
|---|---|---|
| \(\dfrac{13-x}{(x-3)(x+2)} = \dfrac{A}{(x-3)} + \dfrac{B}{(x+2)}\) \(13 - x = A(x+2) + B(x-3)\) | M1 | 1.1a |
| \(A = 2,\ B = -3\) | A1 | 1.1b |
| So \(\dfrac{2}{(x-3)} - \dfrac{3}{(x+2)}\) | A1 | 1.1b |
| [3] |
Notes
M1: Clearing the denominators oe
A1: For one correct coefficient
A1: Correct partial fractions seen
Accept just values for \(A\) and \(B\) if defined